5+2[b-5(2-b)]=

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Solution for 5+2[b-5(2-b)]= equation:


Simplifying
5 + 2[b + -5(2 + -1b)] = 0
5 + 2[b + (2 * -5 + -1b * -5)] = 0
5 + 2[b + (-10 + 5b)] = 0

Reorder the terms:
5 + 2[-10 + b + 5b] = 0

Combine like terms: b + 5b = 6b
5 + 2[-10 + 6b] = 0
5 + [-10 * 2 + 6b * 2] = 0
5 + [-20 + 12b] = 0

Combine like terms: 5 + -20 = -15
-15 + 12b = 0

Solving
-15 + 12b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 12b = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 12b = 0 + 15
12b = 0 + 15

Combine like terms: 0 + 15 = 15
12b = 15

Divide each side by '12'.
b = 1.25

Simplifying
b = 1.25

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